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Diffstat (limited to 'src/swarm/pair.rs')
| -rw-r--r-- | src/swarm/pair.rs | 71 |
1 files changed, 71 insertions, 0 deletions
diff --git a/src/swarm/pair.rs b/src/swarm/pair.rs new file mode 100644 index 0000000..c5e46c7 --- /dev/null +++ b/src/swarm/pair.rs @@ -0,0 +1,71 @@ +//! Which side of a pair of nodes leads, for duties only one side needs to do (opening +//! the sync after a reset, sending keepalive PINGs). +//! +//! Both sides decide on their own, from the two keys alone, and agree. The leader is +//! chosen per pair by one bit of a hash of both keys, not by comparing the keys: a +//! global order would make the node with the smallest key lead every one of its pairs +//! and the one with the largest lead none, so every such duty would pile up on the same +//! few nodes. With the hash, each node leads about half of its pairs. + +use sha2::{Digest, Sha256}; + +const LABEL: &[u8] = b"continuum/pair-leader/1"; + +/// Whether `local` leads its pair with `peer`. Exactly one of `leads(a, b)` and +/// `leads(b, a)` is true for any two different keys. +pub(crate) fn leads(local: &str, peer: &str) -> bool { + let (low, high) = if local <= peer { + (local, peer) + } else { + (peer, local) + }; + let mut hash = Sha256::new(); + // Length-prefixed fields, so no two different pairs hash the same input. + for field in [LABEL, low.as_bytes(), high.as_bytes()] { + hash.update((field.len() as u32).to_be_bytes()); + hash.update(field); + } + let leader = if hash.finalize()[0] & 1 == 0 { low } else { high }; + leader == local +} + +#[cfg(test)] +mod tests { + use super::*; + + fn key(n: u32) -> String { + format!("{:064x}", u64::from(n).wrapping_mul(0x9e37_79b9_7f4a_7c15)) + } + + #[test] + fn exactly_one_side_leads() { + for a in 0..50 { + for b in 0..50 { + if a != b { + assert_ne!(leads(&key(a), &key(b)), leads(&key(b), &key(a))); + } + } + } + } + + #[test] + fn leading_is_spread_across_nodes() { + let nodes: Vec<String> = (0..64).map(key).collect(); + let mut smallest_key_leads = 0; + for (i, node) in nodes.iter().enumerate() { + let led = nodes + .iter() + .filter(|peer| *peer != node && leads(node, peer)) + .count(); + // 63 pairs per node: about half each; far from all or none. + assert!((10..=53).contains(&led), "node {i} leads {led} of 63 pairs"); + for peer in &nodes { + if node < peer && leads(node, peer) { + smallest_key_leads += 1; + } + } + } + // Not simply the smaller key of each pair (64 * 63 / 2 = 2016 pairs). + assert!((800..=1216).contains(&smallest_key_leads), "{smallest_key_leads}"); + } +} |
